How Much Does Dental Implant Cost in Indiana?
Indiana pricing is below the national average. Updated for 2024.
Dental Implant Pricing in Indiana
In Indiana, the average cost for dental implant is $3,080 per tooth, which is 12% lower than the national average of $3,500. Most Indiana residents pay between $1,320 and $5,280.
Indiana benefits from a lower cost of living than many states, resulting in more affordable pricing for dental implant. This makes it one of the more budget-friendly states for this service.
A dental implant is a titanium post surgically placed in the jawbone to replace a missing tooth. The total cost includes the implant, abutment, and crown.
Indiana vs National Average
What Affects Dental Implant Cost in Indiana?
Components
Implant post: $1,000-$2,500. Abutment: $300-$700. Crown: $1,000-$2,500
Bone Grafting
If needed, adds $500-$2,000
Full Mouth
All-on-4 implants: $15,000-$30,000 per arch
💡 Tips to Save on Dental Implant in Indiana
- 1.Get quotes from multiple oral surgeons
- 2.Ask about dental school clinics
- 3.Check if your dental insurance covers any portion
- 4.Consider dental tourism for significant savings
- 5.Ask about payment plans
Frequently Asked Questions
Does insurance cover dental implants?
Most dental insurance covers a portion (usually 50% up to the annual max). Medical insurance may cover if the implant is medically necessary.
How long do dental implants last?
The titanium implant itself can last a lifetime. The crown may need replacement every 10-15 years.